A) \[\frac{hc}{6\lambda }\]
B) \[\frac{hc}{5\lambda }\]
C) \[\frac{hc}{4\lambda }\]
D) \[\frac{2\,hc}{4\lambda }\]
Correct Answer: A
Solution :
\[\frac{hc}{\lambda }=5\,\,e{{V}_{0}}+\phi \] |
\[\frac{hc}{3\lambda }=\,\,e{{V}_{0}}+\phi \] \[\Rightarrow \] \[\frac{2hc}{3\lambda }=\,\,4e{{V}_{0}}\] \[\Rightarrow \] \[\phi =\frac{hc}{6\lambda }\] Ans. |
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