A) 4
B) 2
C) 1
D) 0
Correct Answer: D
Solution :
The given equation can be written as \[\sin x\cos x[{{\sin }^{2}}x+\sin x\cos x+{{\cos }^{2}}x]=1\] or \[\sin x\cos x\left[ 1+\sin x\cos x \right]=1\] or \[\sin 2x\,[2+{{\sin }^{2}}x]=4\]\[\Rightarrow \]\[\sin 2x=\frac{-2\pm \sqrt{4+16}}{2}=-1\pm \sqrt{5}\]Which is not possible.You need to login to perform this action.
You will be redirected in
3 sec