A) 4
B) 3
C) 2
D) 1
Correct Answer: C
Solution :
We have, \[{{\log }_{a}}b={{\log }_{b}}a=c\] \[\Rightarrow \,\,\,{{\log }_{a}}b+\frac{1}{{{\log }_{a}}b}=c\] |
By \[AM\ge GM\] |
\[\therefore \,{{\log }_{a}}b+\frac{1}{{{\log }_{a}}b}\ge 2\] |
\[\therefore \,\,\,\,\,\,\,\,\,c\ge 2\] |
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