In the circuit shown if point O is earthed, the potential of point X is equal to - |
A) 10 V
B) 15V
C) 25 V
D) 12.5V
Correct Answer: B
Solution :
At point D potential is 0. As it is grounded we will write potential drop along the path XCBD |
\[{{V}_{X}}={{V}_{D}}=10-5+10\] (with sign convention) \[{{V}_{X}}-0=15\,\,or\,\,{{V}_{X}}=15\,\,volt\] |
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