A) \[\frac{1}{2}\]
B) \[\frac{36}{55}\]
C) \[\frac{6}{11}\]
D) \[\frac{5}{11}\]
Correct Answer: C
Solution :
We have, x + y + z = 10 |
Total number of sample space \[{{=}^{12}}{{C}_{2}}=66\] |
Number of possibilities of z is even |
\[z=0{{\Rightarrow }^{11}}{{C}_{1}}\]\[\Rightarrow \,\,\,\,\,\,z=2{{\Rightarrow }^{9}}{{C}_{1}}\]\[\Rightarrow \,\,\,\,\,\,z=4{{\Rightarrow }^{9}}{{C}_{1}}\]\[\Rightarrow \,\,\,\,\,\,z=6{{\Rightarrow }^{5}}{{C}_{1}}\]\[\Rightarrow \,\,\,\,\,\,z=8{{\Rightarrow }^{3}}{{C}_{1}}\] |
\[\Rightarrow \,\,\,\,\,\,z=10{{\Rightarrow }^{1}}{{C}_{1}}\] |
Total =11+ 9+7+5+3+1=36, Required probability \[=\frac{36}{66}=\frac{6}{11}\] |
You need to login to perform this action.
You will be redirected in
3 sec