In the circuit diagram shown, \[{{X}_{C}}=100\Omega ,\]\[{{X}_{L}}=200\Omega \] & \[R=100\Omega .\] The effective current through the source is - |
A) 2A
B) \[2\sqrt{2}A\]
C) 0.5 A
D) \[\sqrt{0.4}\,A\]
Correct Answer: B
Solution :
\[{{I}_{R}}=\frac{V}{R}=\frac{200}{100}=2A\] |
\[I'=\frac{V}{{{X}_{L}}-{{X}_{C}}}=\frac{200}{100}=2A\] |
\[I=\sqrt{I_{R}^{2}+I{{'}^{2}}}=2\sqrt{2}\,\,Amp.\] |
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