A) 3
B) 4
C) 5
D) 6
Correct Answer: B
Solution :
Given, harmonic mean of a and b is 4 | |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,4=\frac{2ab}{a+b}\,\,\] | ?. (i) |
And a, 5, q, b are in AP | |
\[\therefore \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,q=10-a,q=\frac{b+5}{2}\]\[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,a=10-q,b=2q-5\] | |
On putting, the values of a and b in Eq. (i), we get | |
\[4=\frac{2\left( 10-q \right)\left( 2q-5 \right)}{10-q+2q-5}\]\[\Rightarrow \,\,2{{q}^{2}}-23q+60=0\]\[\Rightarrow \,\,2{{q}^{2}}-15q-8q+60=0\]\[\Rightarrow \,\,\left( 2q-15 \right)\left( q-4 \right)=0\]\[\Rightarrow \,\,q=4,\frac{15}{2}\] |
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