A) A proton and an a-particle after getting accelerated through same potential difference will have equal penetrating power.
B) Penetrating power of a-particle will be greater than that of proton which have been accelerated by same potential difference.
C) proton's penetrating power will be less than penetrating power of an electron which has been accelerated by the same potential difference.
D) Penetrating powers cannot be compared as all these are particles having no wavelength or wave nature.
Correct Answer: B
Solution :
| \[\lambda =\frac{h}{p}=\frac{h}{\sqrt{2mE}}\] \[\Rightarrow \,\,\,\frac{h}{\sqrt{2m(Vq)}}\] |
| \[\therefore \]For higher m and q; \[\lambda \] will be smaller. |
| For an \[\,'\alpha '\]particle; both ?m? and ?q? are higher Hence lesser is the wavelength. |
| As, (penetrating power) \[\propto Energy\propto \frac{1}{\lambda }\] |
| From above; penetrating power of an \[\alpha \]-particle is more than that of a proton. |
You need to login to perform this action.
You will be redirected in
3 sec
