A) (III) < (IV) < (II) < (I)
B) (IV) < (III) < (I) < (II)
C) (II) < (III) < (IV) < (I)
D) (III) < (II) < (I) < (IV)
Correct Answer: A
Solution :
(I) \[{{C}_{2}}{{H}_{5}}OH\] hydrogen bonding Hydrogen bonding > Dipole-Dipole |
(II) \[{{C}_{2}}{{H}_{5}}Cl\] Dipole-Dipole \[{{C}_{2}}{{H}_{5}}Cl\]is more polar than \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}\]so, Dipole-Dipole \[{{C}_{2}}{{H}_{5}}Cl>\]Dipole- Dipole \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}\] |
(III) \[{{C}_{2}}{{H}_{5}}C{{H}_{3}}\]No hydrogen bonding and dipole -dipole interaction |
(IV) \[{{C}_{2}}{{H}_{5}}OC{{H}_{3}}\]Dipole-Dipole Boiling points order is- (III)< (IV) < (II) < (I). |
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