A) \[{{\operatorname{I}}_{2}}\]
B) \[K{{\operatorname{I}}_{3}}\]
C) \[\operatorname{Bi}{{\left( OH \right)}_{2}}\]
D) \[\operatorname{Bi}\left( OH \right){{\left( N{{O}_{3}} \right)}_{2}}\]
Correct Answer: B
Solution :
At first, \[Bi{{(N{{O}_{3}})}_{3}}\]undergoes hydrolysis nitric acid is formed. Which oxidises KI to iodine. The liberated iodine dissolves in KI to from yellow solutions of \[K{{I}_{3}}\]. |
\[Bi{{(N{{O}_{3}})}_{3}}+{{H}_{2}}O\xrightarrow{{}}[Bi(OH){{(N{{O}_{3}})}_{2}}]+HN{{O}_{3}}\] |
\[2HN{{O}_{3}}\xrightarrow{{}}{{H}_{2}}O+2N{{O}_{2}}+O\] |
\[2KI+{{H}_{2}}O+O\xrightarrow{{}}2KOH+\underset{\operatorname{Drak}\,brown}{\mathop{{{I}_{2}}}}\,\] |
\[{{\operatorname{I}}_{2}}+KI\xrightarrow{{}}\underset{yellow\,\,solution}{\mathop{K{{I}_{3}}}}\,\] |
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