Three batteries of negligible internal resistance and three resistors of 4, 8 and 12 ohm are connected as shown in figure here. The current through the 12 ohm resistor is : |
A) \[0.57A\]
B) \[1.09A\]
C) \[0.04A\]
D) \[1.14A\]
Correct Answer: D
Solution :
In close loop\[BCEDB\], |
\[-4\left( i-i' \right)+10-12i+8=0\] |
and in close loop\[ABDFA\], |
\[-4\left( i-i' \right)+10+8\left( i \right)-6=0\] |
On solving above equations, we get |
\[i=1.14\operatorname{A}.\] |
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