A) \[\frac{{{\mu }_{0}}Q\omega }{2\pi R}\]
B) \[\frac{{{\mu }_{0}}Q\omega }{\pi R}\]
C) \[\frac{{{\mu }_{0}}Q\omega }{4\pi R}\]
D) \[\frac{2{{\mu }_{0}}Q\omega }{\pi R}\]
Correct Answer: A
Solution :
\[dq=\left( \frac{Q}{\pi {{R}^{2}}} \right)\left( 2\pi rdr \right)\] |
\[i=\frac{dq}{T}=\frac{dq}{\left( 2gp/\omega \right)}=\frac{\omega \left( dq \right)}{2\pi }\] |
\[B=\int\limits_{0}^{R}{\frac{{{\mu }_{0}}i}{2r}=\frac{{{\mu }_{0}}}{2}\int\limits_{0}^{R}{\frac{\omega \left( \frac{Q}{\pi {{R}^{2}}} \right)2\pi rdr}{\left( 2\pi \right)r}}}\] |
\[=\frac{{{\mu }_{0}}Q\omega }{2\pi R}\] |
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