A square loop with 2.0 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field is shown in figure. The loop contains a 20.0 V battery with negligible interval resistance. If the magnitude of the field varies with time according to\[B=0.042-0.871t,\], with \[B\] in tesla and t in second. The net emf of the circuit is: |
A) 20.0 V
B) 18.26 V
C) 21.74 V
D) None of these
Correct Answer: C
Solution :
Induced emf, \[\left| \operatorname{e} \right|=\frac{d\phi }{dt}=A\left( \frac{dB}{dt} \right)\] |
\[=\frac{2\times 2}{2}\times \frac{d}{dt}\left( 0.042-0.87t \right)\] \[=2\times 0.87=1.74\operatorname{V}\] |
The net induced emf\[=20+1.74=21.74\]V |
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