A) + 71.5 amp
B) 35.7 amp
C) 142.96 amp
D) 285.93 amp
Correct Answer: A
Solution :
\[2HSO_{4}^{-}\xrightarrow{{}}{{S}_{2}}O_{8}^{-\,-}+2{{H}^{+}}+2{{e}^{-}}\] so required rate \[=1\,\text{mole/hr}\] |
\[=2\,\text{mole}\] of \[{{e}^{-}}\text{/hr}\] |
\[=\frac{2\times 96500}{3600\sec }=\frac{2\times 965}{36}\] |
\[A\simeq 53.6\,A\] |
so required current \[=\frac{4}{3}\times 536.6A=71.4A\] |
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