A) \[1.5\times {{10}^{20}}\]
B) \[7.5\times {{10}^{19}}\]
C) \[3.5\times {{10}^{20}}\]
D) None of these
Correct Answer: B
Solution :
NaCl left \[=\text{1}{{\text{0}}^{-\,3}}-5\times {{10}^{-}}^{\,4}=5\times {{10}^{-\,4}}\text{mol}\] |
No. of unit cells \[=\frac{5}{4}\times {{10}^{-\,4}}\times 6\times {{10}^{23}}=7.5\times {{10}^{19}}\] |
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