Two identical rods of mass M and length \[l\] are lying in a horizontal plane at an angle a. The MI of the system of two rods about an axis passing through \['O'\] and perpendicular to the plane of the rods is |
A) \[Ml{}^{2}/3\]
B) \[Ml{}^{2}/12\]
C) \[Ml{}^{2}/4\]
D) \[Ml{}^{2}/6\]
Correct Answer: D
Solution :
The angle between the rods will not make any difference |
\[I={{I}_{1}}+{{I}_{2}}\] |
\[=\frac{M{{l}^{2}}}{12}+\frac{M{{l}^{2}}}{12}=\frac{M{{l}^{2}}}{6}\] |
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