A) The slit is approximately 0.005 cm wide
B) The slit is approximately 0.05 cm wide
C) \[\operatorname{a}/\lambda \] is approximately 7.5 (a is the slit width)
D) \[\operatorname{a}/\lambda \] is approximately 750
Correct Answer: A
Solution :
\[\sin {{\theta }_{2}}=\frac{2\lambda }{d}\] Or\[{{\theta }_{2}}={{\sin }^{-1}}\left( \frac{2\lambda }{d} \right)\] |
Given \[y=D\left( 2\,{{\theta }_{2}} \right)=8\times {{10}^{-2}}\] |
Or \[1.5\times 2\times {{\sin }^{-1}}\left( \frac{2\lambda }{d} \right)=8\times {{10}^{-2}}\] \[\Rightarrow \]\[d\,\simeq \,0.005\operatorname{cm}\] |
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