A) 8
B) 9
C) 4
D) 12
Correct Answer: D
Solution :
\[{{x}^{2}}+{{y}^{2}}\le 16\]& \[\left| \,x\, \right|\ge y\] |
(unshaded) Area\[=\frac{3}{4}\times \pi \times {{4}^{2}}=12\pi \] |
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