A)
B)
C)
D)
Correct Answer: B
Solution :
\[Ph-OH\xrightarrow{Zn\,\,Dust}Ph-H\xrightarrow[{{H}^{+}}]{C{{H}_{2}}=\,\,CH-\,\,C{{H}_{3}}}\] |
\[Ph-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\xrightarrow[\Delta ]{{{O}_{2}}}\xrightarrow{{{H}_{3}}{{O}^{+}}}Ph-OH+\]\[C{{H}_{3}}-\underset{O}{\mathop{\underset{\parallel }{\mathop{C}}\,}}\,-C{{H}_{3}}\] |
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