A) \[4x+3y-50=0\]
B) \[4x+3y-100=0\]
C) \[4x+3y-46=0\]
D) none of these
Correct Answer: C
Solution :
\[{{S}_{1}}:{{x}^{2}}+{{y}^{2}}=100\] |
Equation of centered at (8, 6) is |
\[{{(x-8)}^{2}}+{{(y-6)}^{2}}=16\] |
\[{{x}^{2}}+{{y}^{2}}-16x-12y+84=0\] |
\[\therefore \] required line AB, (i.e. common chord) |
\[{{S}_{1}}-{{S}_{2}}=0\] |
\[{{x}^{2}}+{{y}^{2}}-16x-12y+84-{{x}^{2}}-{{y}^{2}}+100=0\]\[\Rightarrow -\,16x-12y+184=0\]\[\Rightarrow 4x+3y-46=0\] |
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