A) \[\frac{1}{e},{{e}^{-1/e}}\]
B) \[e,{{e}^{1/e}}\]
C) \[\frac{1}{e},{{e}^{-e}}\]
D) none of these
Correct Answer: A
Solution :
\[f(x)={{x}^{x}}\] |
\[f'(x)={{x}^{x}}(1+\ell nx)=0\] \[\Rightarrow x=\frac{1}{e}\] |
\[\therefore \,\,\,a=\frac{1}{e}\] & \[b={{e}^{-\frac{1}{e}}}\] |
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