A) \[11\times {{10}^{-5}}W\]
B) \[11\times {{10}^{-3}}W\]
C) \[11\times {{10}^{-4}}W\]
D) \[11\times {{10}^{5}}W\]
Correct Answer: A
Solution :
\[R=\frac{P}{{{I}^{2}}}=\frac{4.4}{4\times {{10}^{-6}}}\Omega \] |
\[P'=\frac{{{V}^{2}}}{R}=\frac{11\times 11\times 4\times {{10}^{-6}}}{4.4}W\] |
\[=11\times {{10}^{-5}}W.\] |
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