A) 0.4
B) 0.8
C) 1.2
D) 0.6
Correct Answer: D
Solution :
\[\log \frac{x}{m}=\log k+\frac{1}{n}\log \,\,P\] |
\[y=c+mx\] |
\[\frac{x}{m}=2{{(0.3)}^{1}}=0.6\] |
This is according to Langmuir adsorption isotherm |
x = Amount of adsorbate |
m = Amount of adsorbent |
k = constant |
p = pressure |
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