A)
B)
C)
D)
Correct Answer: A
Solution :
only [A] |
because for positive idoform test either \[-\underset{\underset{OH}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{3}}\] or \[-\underset{\underset{O}{\mathop{\parallel }}\,}{\mathop{C}}\,-C{{H}_{3}}\] group must be present |
\[Ph-\underset{\underset{O}{\mathop{|}}\,}{\mathop{CH}}\,-C{{H}_{3}}\xrightarrow{I{{O}^{\Theta }}}Ph-\underset{\underset{O}{\mathop{\parallel }}\,}{\mathop{C}}\,-C{{H}_{3}}\]\[\xrightarrow{I{{O}^{\Theta }}}Ph-CO{{O}^{\Theta }}+CH{{I}_{3}}\] |
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