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KVPY Sample Paper KVPY Stream-SX Model Paper-28

  • question_answer
    Consider the nuclear fission\[N{{e}^{20}}\to 2H{{e}^{4}}+{{C}^{12}}.\]Given that the binding energy / nucleon of\[N{{e}^{20}},\]\[H{{e}^{4}}\]and\[{{C}^{12}}\]are, respectively, \[8.03\text{ }MeV,\]\[7.07\] \[MeV,\]and\[7.86\text{ }MeV,\] identify the correct statement:

    A) energy of\[12.4\text{ }MeV\]will be supplied

    B) \[8.3\text{ }MeV\]energy will be released

    C) energy of\[3.6\text{ }MeV\]will be released

    D) none of these

    Correct Answer: D

    Solution :

    \[Q={{(B.E.)}_{R}}-{{(B.E.)}_{p}}\]
    \[=20\times 8.03-(8\times 7.07+12\times 7.86)\]
    \[=160.6-(56.56+94.32)\]
    \[\therefore \]\[Q=+9.72me\,V\]
    \[9.72\text{ }MeV\] released.


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