question_answer

A metal plate of area \[1\times {{10}^{-4}}{{m}^{2}}\]is illuminated by a radiation of intensity \[16\text{ }mW/{{m}^{2}}.\] The work function of the metal is \[5eV.\] The energy of the incident photons is 10 eV and only \[10%\] of it produces photo electrons. The number of emitted photo electrons per second and their maximum energy, respectively, will be : \[\left[ 1eV=1.6\times {{10}^{-19}}J \right]\]

A) \[{{10}^{14}}\]and \[10\text{ }eV\]     

B) \[{{10}^{12}}\] and \[5\text{ }eV\]

C) \[{{10}^{11}}\]and \[5\text{ }eV\]  

D) \[{{10}^{10}}\] and \[5\text{ }eV\]