KVPY Sample Paper KVPY Stream-SX Model Paper-28

  • question_answer
    A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is :

    A) \[11\times {{10}^{-5}}W\]

    B) \[11\times {{10}^{-3}}W\]

    C) \[11\times {{10}^{-4}}W\]

    D) \[11\times {{10}^{5}}W\]

    Correct Answer: A

    Solution :

    \[R=\frac{P}{{{I}^{2}}}=\frac{4.4}{4\times {{10}^{-6}}}\Omega \]
    \[P'=\frac{{{V}^{2}}}{R}=\frac{11\times 11\times 4\times {{10}^{-6}}}{4.4}W\]
                \[=11\times {{10}^{-5}}W.\]


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