A) \[4264\pm 81c{{m}^{3}}\]
B) \[4200\pm 81c{{m}^{3}}\]
C) \[4260\pm 80c{{m}^{3}}\]
D) \[4300\pm 80c{{m}^{3}}\]
Correct Answer: C
Solution :
| \[v=\pi {{R}^{2}}h=\frac{\pi }{4}{{D}^{2}}h\]\[=4260c{{m}^{2}}\] |
| \[\because \] \[\frac{\Delta v}{v}=2\frac{\Delta D}{D}+\frac{\Delta h}{h}\] |
| \[=\left( 2\times \frac{0.1}{12.6}+\frac{0.1}{34.2} \right)v\] |
| \[=\frac{2\times 426}{12.6}+\frac{426}{34.2}\] |
| \[=67.61+12.459=80.075\] |
| \[\therefore \] \[v=4260\pm 80c{{m}^{3}}.\] |
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