A) \[2.88\times {{10}^{-4}}se{{c}^{-1}}\]
B) \[1.25\times {{10}^{-4}}se{{c}^{-1}}\]
C) \[5.77\times {{10}^{-4}}se{{c}^{-1}}\]
D) None of these
Correct Answer: C
Solution :
\[k=\frac{2.303}{t}\log \left( \frac{{{P}_{i}}}{{{P}_{t}}} \right);(C{{H}_{3}}){{N}_{2}}\xrightarrow{{}}{{C}_{2}}{{H}_{6}}+{{N}_{2}}\] |
\[\begin{matrix} t=0 & 200\,\,; & t & 200-x & x & x \\ \end{matrix}\] |
as per given \[200+x=350\] \[x=150\] |
\[\therefore \,\,\,k=\frac{2.303}{t}\log \left( \frac{200}{200-150} \right)\] |
\[k=5.77\times {{10}^{-\,4}}{{\sec }^{-\,1}}\] |
You need to login to perform this action.
You will be redirected in
3 sec