A) \[9mA\]
B) \[5mA\]
C) Zero
D) \[14mA\]
Correct Answer: A
Solution :
| \[{{i}_{10k}}=\frac{50}{10k}=5mA\] |
| \[{{i}_{5k}}=\frac{120-50}{5k}=14mA\] |
| \[{{i}_{2}}=(14-5)mA=9mA.\] |
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