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KVPY Sample Paper KVPY Stream-SX Model Paper-28

  • question_answer
    0.3 g of an oxalate salt was dissolved in 100 mL solution. The solution required 90 mL of N/20 \[KMn{{O}_{4}}\] for complete oxidation. The % of oxalate ion in salt is -

    A) 33%

    B) 66%

    C) 70%     

    D) 40%

    Correct Answer: B

    Solution :

    Meq. of oxalate = Meq. of \[KMn{{O}_{4}}\]
    \[\frac{w}{88/2}\times 1000=90\times \frac{1}{20}\]
    \[\therefore \,\,{{w}_{oxalate}}=0.198g\]
    \[%\,oxalate=\frac{0.198}{0.3}\times 100=66%\]


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