A) 5.6 amp
B) 7.2 amp
C) 8.85 amp
D) 11.2 amp
Correct Answer: C
Solution :
Let x gm of Zn deposit on 9 gm of Hg % of Zn in Amalgam\[=\frac{{{m}_{zn}}\times 100}{{{m}_{zn}}\times {{m}_{Hg}}}\] |
\[=\frac{x}{9+x}=100=25\] |
\[\therefore x=3gm\] |
\[Eq.\,\,of\,\,Zn=\frac{3\times 2}{65.4}\] |
\[\frac{{}^{n}{{Z}_{n}}}{1}=\frac{{{n}_{{{e}^{-}}}}}{2}=\frac{Q}{2f}=\frac{it}{2f}\] |
Current =\[\,i=\frac{6}{65.4}\times \frac{96500}{1000}=8.85amp.\] |
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