A) Atomic number of H-like species is 2.
B) Ionization energy of H-like species is 122.4 eV.
C) Kinetic energy of electron in 1st orbit is 50.4 eV
D) Energy of third orbit is \[-13.6\text{ }eV\]
Correct Answer: A
Solution :
\[{{E}_{2}}-{{E}_{1}}=\Delta E\] |
\[40.8=13.6{{Z}^{2}}\left( \frac{1}{1}-\frac{1}{4} \right)=13.6\times \frac{3}{4}{{Z}^{2}}\] |
\[{{Z}^{2}}=4\Rightarrow Z=2\] |
\[IE=13.6\,\,\,{{Z}^{2}}=13.6\times {{2}^{2}}=54.4\,\,ev\] |
\[K{{E}_{1}}=13.6\,\,{{Z}^{2}}=13.6\times {{2}^{2}}=54.4\,\,ev\] |
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