| Charges \[-q\] and \[+q\] located at A and B, respectively, constitute an electric dipole. Distance \[AB=2a,\text{ O}\]is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where \[OP=y\] and \[y>>2a.\] The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P' such that \[OP'=\left( \frac{y}{3} \right),\]the force on Q will be close to: \[\left( \frac{y}{3}>>2a \right)\] |
 |
A) \[3F\]
B) \[\frac{F}{3}\]
C) \[9F\]
D) \[27F\]
Correct Answer: D
Solution :
| \[\because \] \[F\propto \frac{1}{{{r}^{3}}}\] |
| Required force\[=27\text{ }F.\] |
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