A) -1
B) 1
C) 0
D) None of these
Correct Answer: B
Solution :
Let \[z=\sin \ln {{\left( {{i}^{i}} \right)}^{{{i}^{2}}}}+\cos \ln {{\left( {{i}^{i}} \right)}^{{{i}^{2}}}}\] |
\[=\sin \left\{ \ln {{\left( {{e}^{\frac{\pi }{2}}} \right)}^{-1}} \right\}+\cos \left\{ \ln {{\left( {{e}^{-\frac{\pi }{2}}} \right)}^{-1}} \right\}\] |
\[=\sin \frac{\pi }{2}+\cos \frac{\pi }{2}=1\] |
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