A) 1/18
B) 1/9
C) 2/9
D) 1/36
Correct Answer: C
Solution :
\[{{r}_{1}},{{r}_{2}},{{r}_{3}}\in \left\{ 1,2,3,4,5,6 \right\}\] |
\[{{r}_{1}},{{r}_{2}},{{r}_{3}}\].are of the form \[3k,3k+1,3\text{ }k+2\] |
Required probability |
\[a=\frac{3!\times {{\,}^{2}}{{C}_{1}}\times {{\,}^{2}}{{C}_{1}}\times {{\,}^{2}}{{C}_{1}}}{6\times 6\times 6}=\frac{6\times 8}{216}=\frac{2}{9}.\] |
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