A) \[{{10}^{14}}\]and \[10\text{ }eV\]
B) \[{{10}^{12}}\] and \[5\text{ }eV\]
C) \[{{10}^{11}}\]and \[5\text{ }eV\]
D) \[{{10}^{10}}\] and \[5\text{ }eV\]
Correct Answer: C
Solution :
\[n=\frac{16\times {{10}^{-3}}\times {{10}^{-4}}}{10\times 10\times {{10}^{-19}}}\simeq 1.6\times {{10}^{11}}\] |
\[{{(K.E.)}_{\max }}=(10-5)eV=5eV\] |
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