A) \[-\,410\,\,kJ\,\,mo{{l}^{-1}}\]
B) \[-\,752\,\,kJ\,\,mo{{l}^{-1}}\]
C) \[-\,820\,\,kJ\,\,mo{{l}^{-1}}\]
D) \[-\,341.81\,\,kJ\,\,mo{{l}^{-1}}\]
Correct Answer: A
Solution :
\[\Delta {{H}_{solution}}=\Delta {{H}_{1\,\,attice}}+\Delta {{H}_{Hydration}}\] \[\Delta {{H}_{hydration}}=4-756=-752\,\,kJ(a\,\,KJ))\] \[\Delta {{H}_{N{{a}^{+}}hydration}}=\frac{6a}{11}=\frac{6x-752}{11}=-\,410.18\,\,kJ\]You need to login to perform this action.
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