A) \[3\sqrt{2}\]
B) \[2\sqrt{11}\]
C) \[8\sqrt{2}\]
D) \[6\sqrt{3}\]
Correct Answer: D
Solution :
\[x=\sqrt{2}y-4\sqrt{2}\] |
\[{{x}^{2}}=4y\] |
Solving we get point of intersection |
\[A(-2\sqrt{2},2),B(4\sqrt{2},8)\] |
\[\therefore \] \[AB=\sqrt{{{(6\sqrt{2})}^{2}}+{{6}^{2}}}=6\sqrt{3}.\] |
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