A) \[\frac{2{{a}^{2}}}{3a-b}\]
B) \[a-b\]
C) \[2a-b\]
D) \[a/b\]
Correct Answer: A
Solution :
\[x=A\cos \,wt\] (as it starts from rest at t=0) |
\[A-a=A\cos w\] ...(1) |
\[A-(a+b)=A\cos 2w\] ...(2) |
Solving (1) and (2) for A we get \[A=\frac{2{{a}^{2}}}{3a-b}\] |
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