A) \[I(z)=0\]
B) \[R(z)>0\] and \[I(z)>0\]
C) \[R(z)<0\]and \[I(z)>0\]
D) \[R(z)=-3\]
Correct Answer: D
Solution :
\[{{\left( \frac{\sqrt{3}}{2}+\frac{i}{2} \right)}^{5}}={{\left( {{e}^{i\frac{\pi }{b}}} \right)}^{5}}={{e}^{i5\pi /6}}\] |
\[\therefore \] \[z=2\cos \frac{5\pi }{6}=2\left( -\frac{\sqrt{3}}{2} \right)=-\sqrt{3}\] |
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