A uniform triangular wedge of mass M is kept on smooth horizontal surface. A horizontal force F is applied on the wedge, then net force on the upper portion ABC is (AB = l/2 and neglect any effect of rotation) |
A) F/4
B) F/3
C) F
D) 2F
Correct Answer: A
Solution :
\[M\propto \frac{1}{2}{{l}^{2}}\] |
Mass of ABC \[m\propto \frac{1}{2}\frac{{{l}^{2}}}{4}\] ;\[m=\frac{M}{4},\] \[F=Ma\] |
\[F\,\,on\,\,ABC\,\,=\frac{M}{4}a=F/4\] |
\[\therefore \] Ans. [A]. |
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