In the shown figure a battery (ideal) is joined between terminals A and B having EMF=E. Find the current supplied by the battery : |
A) \[\frac{8E}{R}\]
B) \[\frac{8E}{3R}\]
C) \[\frac{4E}{R}\]
D) \[\frac{4E}{3R}\]
Correct Answer: B
Solution :
As potential of points \[{{O}_{1}},{{O}_{2}},{{O}_{3}}\]and \[{{O}_{4}}\] is same |
Hence, Equivalent circuit. |
\[\Rightarrow {{R}_{eq.}}=\frac{3R}{8}\] Hence, \[\therefore \,\,I=\frac{8E}{3R}\] |
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