A) \[509.5\]
B) \[586.5\]
C) \[582.5\]
D) \[507.5\]
Correct Answer: D
Solution :
\[\sum{x}=50\] |
\[{{(3)}^{2}}=\frac{1}{5}\left( e{{x}^{2}}-\frac{{{(ex)}^{2}}}{5} \right)\] |
\[9=\frac{1}{5}\left( \sum{{{x}^{2}}-\frac{2500}{5}} \right)\] |
\[\therefore \] \[\sum{{{x}^{2}}=545}\] |
New variable\[=\frac{1}{6}\left( 3045-\frac{0}{6} \right)=507.5\] |
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