A) third
B) second
C) first
D) fourth
Correct Answer: B
Solution :
\[\frac{k-3}{h-4}=0\] \[k=3\] |
\[\frac{k}{h}=-\frac{4-0}{3-2}\] \[-4h=k\] |
\[h=\frac{-3}{4}.\] |
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