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KVPY Sample Paper KVPY Stream-SX Model Paper-2

  • question_answer
    The octahedral complex of a metal ion \[{{M}^{3+}}\]with four monodentate ligands \[{{L}_{1}},{{L}_{2}},{{L}_{3}}\]and \[{{L}_{4}}\]absorb wavelength in the region of red, green, yellow and blue, respectively. The increasing order of ligand strength of the four  ligands is:

    A) \[{{L}_{4}}<{{L}_{3}}<{{L}_{2}}<{{L}_{1}}\]       

    B) \[{{L}_{1}}<{{L}_{2}}<{{L}_{3}}<{{L}_{4}}\]

    C) \[{{L}_{3}}<{{L}_{2}}<{{L}_{4}}<{{L}_{1}}\]       

    D) \[{{L}_{1}}<{{L}_{2}}<{{L}_{4}}<{{L}_{3}}\]

    Correct Answer: B

    Solution :

    [b] For a given metal ion, weak field ligands create a complex with smaller A, which will absorbs light of longer X and thus lower frequency. Conservely, stronger field ligands create a larger A, absorb light of shorter \[\lambda \] and thus higher v i.e. higher energy. \[\underset{\lambda \,\,=\,\,650\,\,nm}{\mathop{Red}}\,<\text{ }\underset{570\,\,nm}{\mathop{yellow}}\,\text{ }<\text{ }\underset{490\,\,nm}{\mathop{green\text{ }}}\,<\,\,\underset{450\,\,nm}{\mathop{Blue}}\,~\] So order of ligand strength is \[{{L}_{1}}<{{L}_{3}}<{{L}_{2}}<{{L}_{4}}\]


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