A) 10 second: His
B) \[20\text{ }second\text{ }:\,{{O}_{2}}\]
C) 25 second: CO
D) \[~55\text{ }second\text{ }:\,C{{O}_{2}}\]
Correct Answer: B
Solution :
[b]| Under identical conditions,\[\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] |
| As rate of diffusion is also inversely proportional to time, we will have, \[\frac{{{t}_{2}}}{{{t}_{1}}}=\sqrt{\frac{{{M}_{2}}}{{{M}_{1}}}}\] |
| [a] Thus, for he,\[{{t}_{2}}=\sqrt{\frac{4}{2}}\left( 5s \right)=5\sqrt{2s}\ne 10s\] |
| [b] For \[{{O}_{2}},{{t}_{2}}=\sqrt{\frac{32}{2}}(5s)=20s\] |
| [c] For\[CO,{{t}_{2}}=\sqrt{\frac{28}{2}}(5s)\ne 25s\] |
| [d] For\[C{{O}_{2}},{{t}_{2}}=\sqrt{\frac{44}{2}}(5s)\ne 55s\] |
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