A) \[1\pm i\]
B) \[-1\pm i\]
C) \[\omega \] or \[{{\omega }^{2}}\]
D) \[-\,\omega \] or \[{{\omega }^{2}}\]
Correct Answer: A
Solution :
\[x=\sqrt{-\,2+2x}\] \[{{x}^{2}}-2x+2=0\]
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