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KVPY Sample Paper KVPY Stream-SX Model Paper-2

  • question_answer
    For AB bond if percent ionic character is plotted against electronegativity difference \[({{X}_{A}}-{{X}_{B}}),\]the shape of the curve would look like The correct curve is

    A) [A]                   

    B) [B]

    C) [C]                   

    D) [D]

    Correct Answer: C

    Solution :

    [c] Percent ionic character is given by following equation.   % of ionic character \[=16\left( {{X}_{A}}-{{X}_{B}} \right)+3.5{{\left( {{X}_{A}}-{{X}_{B}} \right)}^{2}}\] From the above relation, it is clear that as soon as \[\left( {{X}_{A}}-{{X}_{B}} \right)\]increase. % ionic character will also increase, therefore, curve C show a correct path.    


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