A) \[0.250\]
B) \[0.125\]
C) \[0.100\]
D) \[0.075\]
Correct Answer: D
Solution :
[d]| Mole fraction, \[X=\frac{\frac{w}{m}}{\frac{w}{m}+\frac{W}{M}}\] |
| (Where w and m represent the mass and molar mass of solute and W and M represent the mass and molar mass of solvent) |
| \[\frac{1}{x}=\frac{\frac{w}{m}+\frac{W}{M}}{\frac{w}{m}}\] |
| \[\frac{1}{x}=1+\frac{W\times m}{M\times w}\times \frac{1000}{1000}\] |
| \[\frac{1}{x}=1+\frac{1000}{M\times w}\left( \therefore MOlarity,m=\frac{w\times 1000}{m\times W} \right)\] |
| \[=1+\frac{1000}{18\times 4.5}\] |
| (\[\therefore \]molar mass of \[{{H}_{2}}O=18\]\[mo{{l}^{-1}}\])\[=1+\frac{1000}{81}=13.34\] |
| \[x=\frac{1}{13.34}=0.075\] |
You need to login to perform this action.
You will be redirected in
3 sec
